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Question: The trajectory of a projectile is represented by \(y = \sqrt{3}x - gx^{2} ⥂ / ⥂ 2\). The angle of p...

The trajectory of a projectile is represented by

y=3x−gx2⥂/⥂2y = \sqrt{3}x - gx^{2} ⥂ / ⥂ 2. The angle of projection is

A

300

B

450

C

600

D

None of these

Answer

600

Explanation

Solution

By comparing the coefficient of x in given equation with standard equation y=xtan⁡θ−gx22u2cos⁡2θy = x \tan \theta - \frac { g x ^ { 2 } } { 2 u ^ { 2 } \cos ^ { 2 } \theta } tan⁡θ=3\tan\theta = \sqrt{3}

∴θ=60∘\therefore\theta = 60{^\circ}