Question
Question: The total vapor pressure \[{{P}_{total}}\] (in torr) for a mixture of two volatile components a and ...
The total vapor pressure Ptotal (in torr) for a mixture of two volatile components a and B is given by
Ptotal=220−110XB
Where XB is mole fraction of component , B is mixture.Hence pressure (in torr) of pure component, A and B are respectively:
A) 110, 220
B) 220, 110
C) 220,330
D) 220, 150
Solution
Hint The Raoult’s law states that the solvent partial vapor pressure in a solution or the mixture is equal to the product of vapor pressure of the pure solvent and mole fraction of the solution. There are either positive deviations for Raoult law and negative deviations for Raoult law. The positive deviation occurs when the vapor pressure of solution is higher than it is expected from Raoult law.
Complete solution:
Ptotal=PA+PB……..equation 1
Here PAis the vapour pressure of pure solvent A
PBIs the vapour pressure of pure solvent B
Ptotal=PoAXA+PBoXB……..equation 2
Here PoA is the partial pressure of A
PBoIs the partial pressure of B
XAIs the mole fraction of A
XBIs the mole fraction of B
The equation given to us is
Ptotal=220−110XB…….equation3
On comparing equation 3 with equation 1 we get
PA+PB=220−110XB
So from this we came to know that PA=220 andPB=−110XB …..equation 4
On simplifying equation 2 we get one more formula and that is
Ptotal=XB(PBo−PoA)+PoA
Now on simplifying we get