Question

The total spin resulting from a d7 configuration is:

• A. 1
• B. 2
• C. 5/2
• D. 3/2

Answer 1

Answer: (D)

3/2

Answer 2

d7 : 3 unpaired electrons.

$\therefore$ Total spin

$= \pm \frac{n}{2} = \pm \frac{3}{2}.$