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Question

Physics Question on thermal properties of matter

The total radiant energy per unit area, normal to the direction of incidence, received at a distance RR from the center of a star of radius rr, whose outer surface radiates as a black body at a temperature TKT K is given by (where σ\sigma is Stefan's constant)

A

σr2T4R2\frac{\sigma r^2T^4}{R^2}

B

σr2T44πr2\frac{\sigma r^2T^4}{4\pi r^2}

C

σr4T4r4\frac{\sigma r^4T^4}{r^4}

D

4πσr2T4R2\frac{4\pi\sigma r^2T^4}{R^2}

Answer

σr2T4R2\frac{\sigma r^2T^4}{R^2}

Explanation

Solution

Total radiant energy per unit area
=σ(4πr2)T44πR2=σr2T4R2=\frac{\sigma\left(4 \pi r ^{2}\right) T ^{4}}{4 \pi R ^{2}}=\frac{\sigma r^{2} T ^{4}}{ R ^{2}}