Question

The total pressure observed at equilibrium in the dissociation of solid ammonium carbamate at a certain temperature is 2.0 atm. The equilibrium constant $K _ { p }$ is

• A. 4.185
• B. 1.185
• C. 2.276
• D. 1.072

Answer 1

Answer: (B)

1.185

Answer 2

$\mathrm { NH } _ { 4 } \mathrm { COONH } _ { 2 } ( \mathrm {~s} )$ ⇌

$K _ { p } = P _ { N H _ { 3 } } ^ { 2 } P _ { C O _ { 2 } } = \left( \frac { 2 } { 3 } P \right) ^ { 2 } \left( \frac { 1 } { 3 } P \right) = \frac { 4 } { 27 } P ^ { 3 } = \frac { 4 } { 27 } \times ( 2 ) ^ { 3 } = 1.185$