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Question: The total percentage of magnesium present in magnesium nitrate crystals \( \left[ Mg{{(N{{O}_{3}})}_...

The total percentage of magnesium present in magnesium nitrate crystals [Mg(NO3)26H2O]\left[ Mg{{(N{{O}_{3}})}_{2}}\cdot 6{{H}_{2}}O \right] is [Mg=24;N=14;O=16;H=1][Mg=24;N=14;O=16;H=1]
(A) 9.389.38%
(B) 18.7618.76%
(C) 11.9311.93%
(D) 27.4327.43%

Explanation

Solution

We know that the relative mass of an object is the mass of the object compared to that of a standard object. Mass number and abundance of isotopes tell about the relative atomic masses. Atomic mass is different from atomic number.

Complete answer:
Atom has a nucleus containing protons, neutrons and electrons revolving around the shell. Mass of the atom is negligible. Therefore relative atomic mass can be used. . Relative atomic mass is the average mass of one atom when compared with 12th\dfrac{1}{2}th of mass of carbon-12 atom. Carbon is taken as a standard because only a carbon atom has exactly a whole number as its mass. Relative molecular mass of a molecule is the sum of relative atomic masses of all the atoms in a molecule. Relative formula mass of a molecule is the sum of relative atomic masses of all atoms in the formula. Chemical formula of magnesium nitrate is given as [Mg(NO3)26H2O]\left[ Mg{{(N{{O}_{3}})}_{2}}\cdot 6{{H}_{2}}O \right]
Generally atomic mass is the number of protons and neutrons in an atom. Calculation of relative formula mass: First calculate the number of each element in the molecule with the given formula. Add the atomic masses of each element
Molar mass of [Mg(NO3)26H2O]=256gm.\left[ Mg{{(N{{O}_{3}})}_{2}}\cdot 6{{H}_{2}}O \right]=256gm.
So, the percentage of magnesium is given by =24×100256.4=9.38=24\times \dfrac{100}{256.4}=9.38%. here 2424 is atomic mass of magnesium.
Therefore, the correct answer is option A.

Note:
Remember that generally atomic mass is the weight of an atom. 12th\dfrac{1}{2}th of mass of the carbon12carbon-12 atom is termed as (atomic unit mass). Mass of one carbon atom is 12amu.12amu. Relative formula masses of ionic compounds can also be calculated using this method.