Question
Question: The total percentage of magnesium present in magnesium nitrate crystals \( \left[ Mg{{(N{{O}_{3}})}_...
The total percentage of magnesium present in magnesium nitrate crystals [Mg(NO3)2⋅6H2O] is [Mg=24;N=14;O=16;H=1]
(A) 9.38
(B) 18.76
(C) 11.93
(D) 27.43
Solution
We know that the relative mass of an object is the mass of the object compared to that of a standard object. Mass number and abundance of isotopes tell about the relative atomic masses. Atomic mass is different from atomic number.
Complete answer:
Atom has a nucleus containing protons, neutrons and electrons revolving around the shell. Mass of the atom is negligible. Therefore relative atomic mass can be used. . Relative atomic mass is the average mass of one atom when compared with 21th of mass of carbon-12 atom. Carbon is taken as a standard because only a carbon atom has exactly a whole number as its mass. Relative molecular mass of a molecule is the sum of relative atomic masses of all the atoms in a molecule. Relative formula mass of a molecule is the sum of relative atomic masses of all atoms in the formula. Chemical formula of magnesium nitrate is given as [Mg(NO3)2⋅6H2O]
Generally atomic mass is the number of protons and neutrons in an atom. Calculation of relative formula mass: First calculate the number of each element in the molecule with the given formula. Add the atomic masses of each element
Molar mass of [Mg(NO3)2⋅6H2O]=256gm.
So, the percentage of magnesium is given by =24×256.4100=9.38 here 24 is atomic mass of magnesium.
Therefore, the correct answer is option A.
Note:
Remember that generally atomic mass is the weight of an atom. 21th of mass of the carbon−12 atom is termed as (atomic unit mass). Mass of one carbon atom is 12amu. Relative formula masses of ionic compounds can also be calculated using this method.