Question
Quantitative Aptitude Question on Percentage
The total of male and female populations in a city increased by 25% from 1970 to1980.During the same period,the male population increased by 40% while the female population increased by 20%. From 1980 to 1990, the female population increased by 25%. In 1990, if the female population is twice the male population, then the percentage increase in the total of male and female populations in the city from 1970 to 1990 is
68.75
68.50
68.25
69.25
68.75
Solution
Let the initial male population in 1970 be M and the initial female population in 1970 be F.
Given:
Total population in 1970 = M+F From 1970 to 1980:
Male population increased by 40% → Male population in 1980 =1.4M
Female population increased by 20% → Female population in 1980 = 1.2F
Total population in 1980 = 1.4M+1.2F
Given that the total population increased by 25% from 1970 to 1980:
1.4M+1.2F=1.25(M+F)
1.4M+1.2F=1.25M+1.25F
0.15M=0.05F
3M=F
This gives the relation between the male and female populations in 1970.
From 1980 to 1990:
Female population increased by 25% → Female population in 1990 =1.25×1.2F=1.5F
Given that in 1990, the female population is twice the male population:
1.5F=2×Male population in 1990
Male population in 1990=0.75F
Since no information is provided about how the male population changed from 1980 to 1990, we'll use the relation from the previous decade:
Male population in 1980 = 1.4M Given that M=3F Male population in 1980 = 1.4×3F= 0.4667F
Now, comparing male populations from 1980 and 1990:
0.4667F→0.75F
The male population increased by 0.2833F or approximately 60.7% of the male population in 1980.
Total population in 1990 = 1.5F+0.75F=2.25F
The total population in 1970 = M+F = 3F+F=34F
Percentage increase from 1970 to 1990:
34F(2.25F−34F)×100
4F6.75F−4F×100
4F2.75F×100
=68.75%
Thus, the percentage increase in the total of male and female populations in the city from 1970 to 1990 is 68.75