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Chemistry Question on Mole concept and Molar Masses

The total number of protons in 10 g 10\,g of calcium carbonate is (N0=6.023×1023) (N_{0}=6.023\times 10^{23}) :

A

3.01×1024 3.01\times 10^{24}

B

4.06×1024 4.06\times 10^{24}

C

2.01×1024 2.01\times 10^{24}

D

3.02×1024 3.02\times 10^{24}

Answer

3.01×1024 3.01\times 10^{24}

Explanation

Solution

We know that protons in 11 mole CaCO3CaCO_3

=atomic number of calcium+atomic number of carbon+3(atomic number of oxygen)\text{atomic number of calcium} +\text{atomic number of carbon} +3(\text{atomic number of oxygen})

= 20+6+3(8)=5020+6+3 (8) =50

1010 g CaCO3CaCO_3 contain

=50×10100\frac{50×10}{100} moles of protons

Count of Protons = 5×6.02×10235 × 6.02 × 10 ^{23}

= 3.01×10243.01 × 10 ^{24}

Therefore, the correct option is (A): 3.01×10243.01 × 10 ^{24}