Question

The total number of possible isomers for the complex compound $[Cu^{II}(NH_3)_4] [Pt^{II}Cl_4]$ are

• A. 5
• B. 6
• C. 3
• D. 4

Answer 1

Answer: (D)

4

Answer 2

Total isomers of the given complex are four.
These are
$(i) [ Cu ( NH_3)_4 ] [PtCl_4 ]$
$(ii) [Cu (NH_3)_3Cl] [Pt(NH_3)Cl_3 ]$
$(hi) [Pt(NH_3)_3Cl] [Cu (NH_3)Cl_3]$
$(iv) [Pt(NH_3)_4] [CuCl_4]$