Question

The total number of orbitals in an energy level designated by principal quantum number $n$ is equal to

• A. $2n$
• B. $2n^{2}$
• C. $n$
• D. $n^{2}$

Answer 1

Answer: (D)

$n^{2}$

Answer 2

No. of electrons$= 2n^{2}$hence no. of orbital

$= \frac{2n^{2}}{2} = n^{2}$.