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Question

Question: The total number of \(\alpha\) - and \(\beta\) -particles given out during given nuclear transformat...

The total number of α\alpha - and β\beta -particles given out during given nuclear transformation is

A

2

B

4

C

6

D

8

Answer

8

Explanation

Solution

92238U82214Pb+m24He+n10e{}_{92}^{238}U{\overset{\quad\quad}{\rightarrow}}_{82}^{214}P{b_{+ m}}_{2}^{4}H{e_{+ n}}_{- 1}^{0}e

m=6andm=2.Total=8.\therefore m = 6andm = 2. Total = 8.