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Question: The total length of potentiometer wire is 10 m. The distance between the null points on the potentio...

The total length of potentiometer wire is 10 m. The distance between the null points on the potentiometer wire for two cells is 60 cm. If the difference between the emfs of the cells be 0.4 V, the potential qradient along the wire is –

A

32V/m\frac{3}{2}V/m

B

13V/m\frac{1}{3}V/m

C

23V/m\frac{2}{3}V/m

D

12V/m\frac{1}{2}V/m

Answer

23V/m\frac{2}{3}V/m

Explanation

Solution

l1 – l2 = 60 cm

E1 – E2 = 0.4

kl1 – kl2 = 0.4

k(l1 –l2) = 0.4

k = 0.460\frac { 0.4 } { 60 } = 23\frac { 2 } { 3 }V/m