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Question: The total kinetic energy of a body of mass 10 kg and radius 0.5 m moving with a velocity of 2 m/s wi...

The total kinetic energy of a body of mass 10 kg and radius 0.5 m moving with a velocity of 2 m/s without slipping is 32.8 joule. The radius of gyrationof the body is:

A

0.25 m

B

0.2 m

C

0.5 m

D

0.4 m.

Answer

0.4 m.

Explanation

Solution

d)

Sol. Total kinetic energy

=

12×10×(2)2(1+K2(0.5)2)=32.8\Rightarrow \frac { 1 } { 2 } \times 10 \times ( 2 ) ^ { 2 } \left( 1 + \frac { K ^ { 2 } } { ( 0.5 ) ^ { 2 } } \right) = 32.8