Question

The total kinetic energy of 1 mole of oxygen at 27°C is :
[Use universal gas constant (R)= 8.31 J/mole K]

• A. 6232.5 J
• B. 6845.5 J
• C. 5942.0 J
• D. 5670.5 J

Answer 1

Answer: (A)

6232.5 J

Answer 2

The kinetic energy of a gas is given by:

$E = \frac{f}{2} nRT,$

where $f$ is the degrees of freedom.

For a diatomic gas like oxygen:
- $f = 5$,
- $n = 1$,
- $R = 8.31 \, \text{J/mol·K}$,
- $T = 27^\circ \text{C} = 300 \, \text{K}$.

Substituting the values:

$E = \frac{5}{2} \times 1 \times 8.31 \times 300 = 6232.5 \, \text{J}.$

The correct option is (A) : 6232.5 J