Question

The total internal energy of two mole monoatomic ideal gas at temperature T =300 K will be _____J.
(Given _R _= 8.31 J/mol.K)

Answer 1

The correct answer is 7479
$U = 2 ( \frac{3}{2} R ) 300$
= 3 × 8.31 × 300
= 7479 J