Question

The total energy of an electron in the $n^{th}$ stationary orbit of the hydrogen atom can be obtained by

• A. $E_{n}=\frac{13.6}{n^{2}} eV$
• B. $E_{n}=-\frac{13.6}{n^{2}} eV$
• C. $E_{n}=-\frac{1.36}{n^{2}}eV$
• D. $E_{n}=-13.6\times n^{2}eV$

Answer 1

Answer: (B)

$E_{n}=-\frac{13.6}{n^{2}} eV$

Answer 2

For hydrogen $E=-\frac{13.6}{n^{2}}eV$