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Question: The total energy of an electron in the first excited state of hydrogen atom is about –3.4 eV. Its KE...

The total energy of an electron in the first excited state of hydrogen atom is about –3.4 eV. Its KE in this state is –

A

3.4 eV

B

6.8 eV

C

– 3.4 eV

D

– 6.8 eV

Answer

3.4 eV

Explanation

Solution

– K.E. = T.E = P.E2\frac{P.E}{2}