Question

The total electric flux emanating from a closed surface enclosing an $\alpha$-particle (e = electronic charge) is

• A. $\frac{ 2e}{ \varepsilon_0}$
• B. $\frac{ e}{ \varepsilon_0}$
• C. $e \varepsilon_0$
• D. $\frac{ \varepsilon_0 \, e }{ 4}$

Answer 1

Answer: (A)

$\frac{ 2e}{ \varepsilon_0}$

Answer 2

By Gauss theorem $| \phi_E | = \bigg | \frac{ q}{ \varepsilon_0 } \bigg |$ = $\bigg | \frac{ - 2 e}{ \varepsilon_0 } \bigg |$ $\frac{ q}{ \varepsilon} = \frac{ 2e}{ \varepsilon_0}$