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Question: The torque and magnetic potential energy of a magnetic dipole in most stable position in a uniform m...

The torque and magnetic potential energy of a magnetic dipole in most stable position in a uniform magnetic field

(m\overrightarrow { \mathrm { m } }) will be

A

-mB, zero

B

mB, zero

C

zero, mB

D

zero, -mB.

Answer

zero, -mB.

Explanation

Solution

: Torque,τ=m×B=mBsinθ\vec { \tau } = \overrightarrow { \mathrm { m } } \times \overrightarrow { \mathrm { B } } = \mathrm { mB } \sin \theta

and magnetic potential energy

at θ=0\theta = 0 ^ { \circ } the dipole will be in most stable position τ=msinθ=mBsin0=0\tau = \mathrm { m } \sin \theta = \mathrm { mB } \sin 0 = 0

and,