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Question

Physics Question on mechanical properties of fluid

The top of a water tank is open to air and its water level is maintained. It is giving out 0.74m30.74\, m^3 water per minute through a circular opening of 2cm2\, cm radius in its wall. The depth of the centre of the opening from the level of water in the tank is close to :

A

9.6 m

B

4.8 m

C

2.9 m

D

6.0 m

Answer

4.8 m

Explanation

Solution

In flow volume = outflow volume 0.7460=(π×4×104)×2gh\Rightarrow \frac{0.74}{60} = \left(\pi \times4 \times10^{-4}\right) \times\sqrt{2gh} 2gh=74×100240π\Rightarrow \sqrt{2gh} = \frac{74 \times100}{240 \pi} 2gh74024π\Rightarrow \sqrt{2gh} \frac{740}{24\pi} 2gh=740×74024×24×10(π2=10) \Rightarrow 2gh = \frac{740 \times740 }{24 \times24\times10} \left(\pi^{2} = 10\right) h=74×742×24×24\Rightarrow h = \frac{74 \times74}{2 \times24 \times24} h4.8m\Rightarrow h \approx 4.8 m