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Question

Physics Question on Alternating current

The time taken by AC of 50 Hz in reacting from zero to the maximum value is

A

1×10−2 s1\times10^{-2}\,s

B

2×10−2 s2\times10^{-2}\,s

C

50×10−3 s50\times10^{-3}\,s

D

5×10−3 s5\times10^{-3}\,s

Answer

5×10−3 s5\times10^{-3}\,s

Explanation

Solution

T = 1ν=150\frac{1}{\nu} = \frac{1}{50} For given pondition, t=14×150=1200=5×10−3s.t = \frac{1}{4} \times \frac{1}{50} = \frac{1}{200} = 5 \times 10^{-3}s.