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Question: The time period of an artificial satellite in a circular or bit of radius R is 2 days and its orbita...

The time period of an artificial satellite in a circular or bit of radius R is 2 days and its orbital velocity isIf time period of another satellite in a circular orbit is 16 days then

A

Its radius of orbit is 4R and orbital velocity is

B

Its radius of orbit is 4R and orbital velocity vo2\frac { \mathrm { v } _ { \mathrm { o } } } { 2 } is

C

Its radius of orbit is 2R and orbital velocity is

D

Its radius of orbit is 2R and orbital velocity is

Answer

Its radius of orbit is 4R and orbital velocity vo2\frac { \mathrm { v } _ { \mathrm { o } } } { 2 } is

Explanation

Solution

According to Kepler’s third law

T1 T2=(R1R2)3/2\therefore \frac { \mathrm { T } _ { 1 } } { \mathrm {~T} _ { 2 } } = \left( \frac { \mathrm { R } _ { 1 } } { \mathrm { R } _ { 2 } } \right) ^ { 3 / 2 }

Or R2=(R1)(T2 T1)2/3=(R1)(162)2/3\mathrm { R } _ { 2 } = \left( \mathrm { R } _ { 1 } \right) \left( \frac { \mathrm { T } _ { 2 } } { \mathrm {~T} _ { 1 } } \right) ^ { 2 / 3 } = \left( \mathrm { R } _ { 1 } \right) \left( \frac { 16 } { 2 } \right) ^ { 2 / 3 }

(given ) ….(i)

Orbital velocity,

(using (i))

Or