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Question: The time period of a simple pendulum when it is made to oscillate on the surface of moon...

The time period of a simple pendulum when it is made to oscillate on the surface of moon

A

Increases

B

Decreases

C

Remains unchanged

D

Becomes infinite

Answer

Increases

Explanation

Solution

At the surface of moon, g decreases hence time period increases (asT1g)\left( \text{as}T \propto \frac{1}{\sqrt{g}} \right)