Question

The time period of a simple pendulum on a freely moving artificial satellite is

• A. Zero
• B. 2 sec
• C. 3 sec
• D. Infinite

Answer 1

Answer: (D)

Infinite

Answer 2

$T = 2 \pi \sqrt { \frac { l } { g ^ { \prime } } }$ $= 2 \pi \sqrt { \frac { l } { 0 } } = \infty$

[As $g ^ { \prime } = 0$ in the satellite]