Question

The time period of a simple pendulum is 2 sec. If its length is increased by 4 times, the period becomes

• A. 4 sec.
• B. 6 sec.
• C. 3 sec.
• D. 2 sec.

Answer 1

Answer: (A)

4 sec.

Answer 2

T = 2π$\sqrt{\frac{\mathcal{l}}{g}}$ = 2 sec.

Now, L = 4

∴ T’ = 2π $\sqrt{\frac{4\mathcal{l}}{g}}$ = 4 sec.