Question

The time period of a particle undergoing SHM is 16 s. It starts motion from the mean position. After 2 s, its velocity is 0.4 m s. The amplitude is

• A. 1.44 m
• B. 0.72 m
• C. 2.88 m
• D. 0.36 m

Answer 1

Answer: (A)

1.44 m

Answer 2

Velocity, v = r?cos?t $04=r\times\frac{2\pi}{16} cos \frac{2\pi}{16}\times2=r\times\frac{2\pi}{16}\times\frac{1}{16}\times\frac{1}{\sqrt{2}}$ or $\quad r=\frac{0.4\times16\times\sqrt{2}}{2\pi}=\frac{3.2\sqrt{2}}{\pi}=1.44$ m