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Question

Physics Question on Kinetic molecular theory of gases

The time dependence of a physical quantity PP is given by P=P0eαP(αt2)P=P_{0} e \alpha P\left(-\alpha t^{2}\right) where α\alpha is a constant and tt is time. The constant α\alpha

A

is a dimensionless

B

has dimensions of PP

C

has dimensions of T2T^{-2}

D

has dimensions of T2T^2

Answer

has dimensions of T2T^{-2}

Explanation

Solution

Given, P=P0exp(αt2)P=P_{0} \exp \left(-\alpha t^{2}\right) As PP and P0P_{0} have the same units, therefore αt2\alpha t^{2} must be dimensionless for which α=1T2=T2\alpha=\frac{1}{T^{2}}=T^{-2}