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Question

Mathematics Question on Geometric Progression

The third term of a G.P. is 9. The product of its first five terms is

A

3103^{10}

B

353^5

C

3123^{12}

D

393^9

Answer

3103^{10}

Explanation

Solution

Letar2.ar.a.ar.ar2Let \frac{a}{r^{2}}.\frac{a}{r}.a.ar.ar^{2} are in G.P., Given a = 9 ∴ product=95=310\therefore\, product =9^{5}=3^{10}