Question

The third line of the Balmer series in the emission spectrum of the hydrogen atom is due to the transition from the

• A. fourth Bohr orbit to the first Bohr orbit
• B. fifth Bohr orbit to the second Bohr orbit
• C. sixth Bohr orbit to the third Bohr orbit
• D. seventh Bohr orbit to the third Bohr orbit

Answer 1

Answer: (B)

fifth Bohr orbit to the second Bohr orbit

Answer 2

In Balmer series, $n_1=2$ and $n_2 = 3$, $4$, $5$ So, third line arises by the emission of $5^{th}$ orbit to $2^{nd}$ orbit.