Question

The third line of the balmer series in the emission spectrum of the hydrogen atom is due to the transition from the.

• A. Fourth Bohr orbit to the first Bohr orbit
• B. Fifth Bohr orbit to the second Bohr orbit
• C. Sixth Bohr orbit to the third Bohr orbit
• D. Seventh Bohr orbit to the third Bohr orbit.

Answer 1

Answer: (B)

Fifth Bohr orbit to the second Bohr orbit

Answer 2

: Rydberg’s formula for calculation of wavenumbers of lines in hydrogen spectrum is

$\overset{\_\_}{\upsilon} = R\left\lbrack \frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}} \right\rbrack$

For Balmer series, $n_{1} = 2$ and $n_{2} = 3,4,5,$ so third line of the Balmer series is due to transition from fifth Bohr orbit to second Bohr orbit.