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Question: The thermal conductivity of two materials are in the ratio 1 : 2. What will be the ratio of thermal ...

The thermal conductivity of two materials are in the ratio 1 : 2. What will be the ratio of thermal resistances of rods of these materials having length in the ratio 1 : 2 and area of cross-section in the ratio 1 : 2:

A

1 : 2

B

1 : 4

C

1 : 8

D

1 : 16

Answer

1 : 2

Explanation

Solution

K1A(Th–Tj)L\frac{K_{1}A(T_{h}–T_{j})}{L} = K2A(Tj–Tc)L\frac{K_{2}A(T_{j}–T_{c})}{L}