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Question: The \({\text{p}}{{\text{K}}_{\text{a}}}\) value of acetic acid \({\text{p}}{{\text{K}}_{\text{b}}}\)...

The pKa{\text{p}}{{\text{K}}_{\text{a}}} value of acetic acid pKb{\text{p}}{{\text{K}}_{\text{b}}} value of ammonium hydroxide are 4.764.76 and 4.754.75 respectively. Calculate the pH{\text{pH}} of ammonium acetate solution.
A. 6.026.02
B. 7.0057.005
C. 88
D. 5.6025.602

Explanation

Solution

pH{\text{pH}} means power of hydrogen. It is the negative log of proton concentration. Similarly, pKa{\text{p}}{{\text{K}}_{\text{a}}} is the negative log of Ka{{\text{K}}_{\text{a}}} value. Ka{{\text{K}}_{\text{a}}} value is referred to the equilibrium constant of acid or acid dissociation constant and Kb{{\text{K}}_{\text{b}}} is the equilibrium constant of base or base dissociation constant. They are used to determine the ability to donate or accept the protons.

Complete step by step answer:
pKa{\text{p}}{{\text{K}}_{\text{a}}}, pKb{\text{p}}{{\text{K}}_{\text{b}}} and pH{\text{pH}} are used to measure the strength of acids and bases. It tells how acidic or basic the solution is.
pKa{\text{p}}{{\text{K}}_{\text{a}}} and pKb{\text{p}}{{\text{K}}_{\text{b}}} have a simple relation which is shown below:
pKa+pKb=14{\text{p}}{{\text{K}}_{\text{a}}} + {\text{p}}{{\text{K}}_{\text{b}}} = 14
Ammonium acetate is a salt formed by reacting acetic acid with ammonium hydroxide. Both acid and base are weak. Thus maximum hydrolysis occurs since both are very reactive in water.
Thus pH{\text{pH}} can be written as:
pH=7+12(pKapKb){\text{pH}} = 7 + \dfrac{1}{2}\left( {{\text{p}}{{\text{K}}_{\text{a}}} - {\text{p}}{{\text{K}}_{\text{b}}}} \right)
Substituting the values of pKa{\text{p}}{{\text{K}}_{\text{a}}} and pKb{\text{p}}{{\text{K}}_{\text{b}}}, we get
pH=7+12(4.764.75)=7+0.012=7+0.005=7.005{\text{pH}} = 7 + \dfrac{1}{2}\left( {4.76 - 4.75} \right) = 7 + \dfrac{{0.01}}{2} = 7 + 0.005 = 7.005
Since the pH{\text{pH}} is almost equal to 77, the product formed is neutral.
Hence the option B is correct.

Additional information:
When pKa>pKb{\text{p}}{{\text{K}}_{\text{a}}} > {\text{p}}{{\text{K}}_{\text{b}}}, solution will be alkaline. It is because the acid will be weaker than base. Thus pH{\text{pH}} value will be more than 77.
When pKa < pKb{\text{p}}{{\text{K}}_{\text{a}}}{\text{ < p}}{{\text{K}}_{\text{b}}}, solution will be acidic because acid is comparatively stronger than base. Thus pH{\text{pH}} value will be less than 77.

Note:
In a chemical reaction, when acid is stronger than base, the solution is acidic. When the base is stronger than acid, the solution is basic. When both the acid and base are either strong or weak, the solution will be neutral.