Question

The term independent of x in the expansion of $\left( \frac{4}{9}x^{2} - \frac{3}{2x} \right)^{9}$is

• A. 5^th
• B. 6^th
• C. 7^th
• D. 8^th

Answer 1

Answer: (C)

7^th

Answer 2

Here $\left( \frac{4}{9}x^{2} - \frac{3}{2x} \right)^{9}$ comparing with $\left( x^{\alpha} \pm \frac{1}{x^{\beta}} \right)^{n}$

a = 2, b = 1 n = 9

Ž r = $\frac{9.2}{2 + 1}$= 6

so T_r+1 = T₆₊₁ = T₇ is independent of x.