Question
Mathematics Question on Binomial theorem
The term independent of x in the expansion of (601−81x8).(2x2−x23)6 is equal to:
A
36
B
-108
C
-72
D
-36
Answer
-36
Explanation
Solution
601(2x2−x23)6−811.x8(2x2−x23)6 its general term 6016Cr26−r(−3)rx12−r−8116Cr26−r(−3)r1220−4r for term independent of x,r for Ist expression is 3 and r for second expression is 5 ∴ term independent of x=−36