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Question: The term independent of x in the expansion of \(2^{3n} > 7n + 1\)is....

The term independent of x in the expansion of

23n>7n+12^{3n} > 7n + 1is.

A

(n+12)n≥n!\left( \frac{n + 1}{2} \right)^{n} \geq n!

B

10n−2>81n10^{n - 2} > 81n

C

2n<n!2^{n} < n!

D

3n>n33^{n} > n^{3}

Answer

2n<n!2^{n} < n!

Explanation

Solution

−79- \frac{7}{9} therefore fourth term will be independent of x i.e.

79\frac{7}{9}