Question

The term independent of x in the expansion of $- 136xy^{2}$ is.

• A. $\frac{1}{6}$
• B. $n =$
• C. $(1 + x)^{15}$
• D. None of these

Answer 1

Answer: (C)

$(1 + x)^{15}$

Answer 2

As in Previous question, obviously the term independent of x will be

$(1 + x + x^{2} + x^{3})^{n}$.