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Question: The term independent of x in the expansion \((n!)^{2} > n^{n}\)is ....

The term independent of x in the expansion (n!)2>nn(n!)^{2} > n^{n}is .

A

P(n)⇒P(n+1)P(n) \Rightarrow P(n + 1)

B

PnP_{n}

C

np−nn^{p} - n

D

x(xn−1−nan−1)+an(n−1)x(x^{n - 1} - na^{n - 1}) + a^{n}(n - 1)

Answer

PnP_{n}

Explanation

Solution

In 97\frac{9}{7}

(x+a)n(1+x)n(x + a)^{n}(1 + x)^{n}

It is independent of x.

∴ (p+1)th(p + 1)^{th}

∴ p+q=p + q =.