Question

The temperatures of two bodies A and B are and . The ratio of rate of emission of radiations will be

• A. 727/127
• B. 625/16
• C. 1000/400
• D. 100/16

Answer 1

Answer: (B)

625/16

Answer 2

$\frac { E _ { 1 } } { E _ { 2 } } = \left( \frac { T _ { 1 } } { T _ { 2 } } \right) ^ { 4 } = \left( \frac { 727 + 273 } { 127 + 273 } \right) ^ { 4 }$ $= \frac { ( 1000 ) ^ { 4 } } { ( 400 ) ^ { 4 } } = \frac { 10 ^ { 4 } } { 4 ^ { 4 } } = \frac { 625 } { 16 }$