Solveeit Logo

Question

Physics Question on thermal properties of matter

The temperature of two bodies AA and BB are respectively, 727?C727?C and 327?C327?C. The ratio HA:HBH_A : H_B of the rates of heat radiated by them is

A

727 : 327

B

5:03

C

25:09:00

D

625 : 81

Answer

625 : 81

Explanation

Solution

HAHB=(727+273)4(327+273)4\frac{H_{A}}{H_{B}} =\frac{\left(727 + 273\right)^{4}}{\left(327 +273\right)^{4}}
=(1000600)4=5×5×5×53×3×3×3=62581= \left(\frac{1000}{600}\right)^{4} = \frac{5 \times5\times5\times5}{3\times3\times3\times3} = \frac{625}{81}