Question

The temperature of reservoir of Carnot's engine operating with an efficiency of 70% is 1000K. The temperature of its sink is

• A. 300 K
• B. 400 K
• C. 500 K
• D. 700 K

Answer 1

Answer: (A)

300 K

Answer 2

$\eta = 1 - \frac{T_{2}}{T_{1}}$ ⇒ $\frac{70}{100} = 1 - \frac{T_{2}}{1000}$ ⇒ $T_{2} = 300K$