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Physics Question on thermal properties of matter

The temperature of an object is 60∘C60^{\circ} C. Its value in Fahrenheit scale is

A

120∘120^{\circ} F

B

130∘130^{\circ} F

C

140∘140^{\circ} F

D

110∘110^{\circ} F

Answer

140∘140^{\circ} F

Explanation

Solution

Let TFT_F be temperature on Fahrenheit scale corresponding to 60∘C60^{\circ} C on Celsius scale. Then 60−0100−0=TF−32212−32\frac{60-0}{100-0} = \frac{T_{F} -32}{212 -32} 35=TF−32180 \frac{3}{5} = \frac{T_{F } - 32}{180} 5TF−160=540 5T_{F} - 160 = 540 5TF=7005T_{F} = 700 or TF=7005∘F=140∘FT_{F} = \frac{700}{5}^{\circ}F = 140^{\circ} F