Question

The temperature of an ideal gas is reduced from 927C to 27C. The r.m.s. velocity of the molecules becomes

• A. Double the initial value
• B. Half of the initial value
• C. Four times the initial value
• D. Ten times the initial value

Answer 1

Answer: (B)

Half of the initial value

Answer 2

Temperature becomes $\frac{1}{4}th$ of initial value

$(1200K = 927{^\circ}C \rightarrow 300K = 27{^\circ}C)$

So, using $v_{rms} \propto \sqrt{T}.$ $r.m.s.$ velocity will be half of the initial value.