Question

The temperature of an ideal gas at atmospheric pressure is 300K and volume 1m³. If temperature and volume become double, then pressure will be

• A. $10^{5}N/m^{2}$
• B. $2 \times 10^{5}N/m^{2}$
• C. $0.5 \times 10^{5}N/m^{2}$
• D. $4 \times 10^{5}N/m^{2}$

Answer 1

Answer: (A)

$10^{5}N/m^{2}$

Answer 2

$PV = \mu RT$̃ $P \propto \frac{T}{V}$. If T and V both doubled then pressure remains same i.e. P₂ = P₁ = 1 atm = 1 ´ 10⁵ N/m².