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Question: The temperature of a wire of length 1 metre and area of cross-section \(1 \mathrm {~cm} ^ { 2 }\) is...

The temperature of a wire of length 1 metre and area of cross-section 1 cm21 \mathrm {~cm} ^ { 2 } is increased from 0°C to 100°C. If the rod is not allowed to increase in length, the force required will be and Y=1011 N/m2)\left. Y = 10 ^ { 11 } \mathrm {~N} / \mathrm { m } ^ { 2 } \right)

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Answer
Explanation

Solution

F=F =force developed=YAα(Δθ)= Y A \alpha ( \Delta \theta )