Question
Question: The temperature of a furnace is \(2324^\circ C\) and the intensity is maximum in its spectrum nearly...
The temperature of a furnace is 2324∘C and the intensity is maximum in its spectrum nearly at 12000Ao. If the intensity in the spectrum of a star is maximum nearly at 4800Ao, then the surface temperature of the star is:
(A) 8400∘C
(B) 6219∘C
(C) 7200∘C
(D) 5900∘C
Solution
Hint Wilhelm wein in 1893, found out that the product of temperature of a body and the maximum wavelength or the minimum frequency of the light emerging from that body is a constant. This constant has the same value universally. So, in this question, we need to equate the product of temperature and wavelength of the furnace to the temperature and wavelength of the star.
Complete step by step solution
According to Wein’s displacement law, λmaxT=constant=b
where, λmax is the peak wavelength or the wavelength at which the intensity of the spectrum is maximum, at temperature T and b is a constant.
When the temperature of the furnace is 2324∘C, the intensity of the spectrum is maximum at 12000Ao .
⇒Peak Wavelength=λmax=12000Ao
Putting this in the equation for wien's displacement law gives us,
⇒b=2324∘C×12000Ao
When the temperature is (let’s say), T ∘C, the intensity of the spectrum is maximum at 4800Ao .
⇒Peak Wavelength=λmax=4800Ao
Putting this in equation for wien's displacement law and using the previously calculated value of b,
Note According to wein’s displacement law, λmaxT=constant=b
⇒λmax1T1=λmax1T2
Alternatively, this equation can directly be used to get a quick result.
Also, while substituting the values of temperature, we must not forget to convert ∘C into Kelvin otherwise we will get a misleading/faulty answer.