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Question: The temperature of a body rose by \[40\,^\circ {\text{C}}\] . How much is the increase in the Fahren...

The temperature of a body rose by 40C40\,^\circ {\text{C}} . How much is the increase in the Fahrenheit scale?
A. 8F8\,^\circ {\text{F}}
B. 40F40\,^\circ {\text{F}}
C. 62F62\,^\circ {\text{F}}
D. 72F72\,^\circ {\text{F}}

Explanation

Solution

First we will assume two different temperatures, which are at a difference of 40C40\,^\circ {\text{C}} . After that we will use the relation between the centigrade scale and the Fahrenheit scale to convert them into degree Fahrenheit. After that we will find the difference to obtain the answer.

Formula used:
The formula which gives the relation between the centigrade scale and the Fahrenheit scale is given as follows:
F=9C5+32F = \dfrac{{9C}}{5} + 32 …… (1)
Where,
FF indicates the temperature reading on the Fahrenheit scale.
CC indicates the temperature reading on a centigrade scale.

Complete step by step answer:
To begin with, we will assume two different temperatures which are at a difference of 40C40\,^\circ {\text{C}} .Let the two temperatures be 30C30\,^\circ {\text{C}} and 70C70\,^\circ {\text{C}} .Let us convert these two temperatures in Fahrenheit scale, by substituting the required values in the formula (1) and we get:
For 30C30\,^\circ {\text{C}} :
F = \dfrac{{9C}}{5} + 32 \\\ \Rightarrow F = \dfrac{{9 \times 30}}{5} + 32 \\\ \Rightarrow F = 54 + 32 \\\ \Rightarrow F = 86\,^\circ {\text{F}} \\\
For 70C70\,^\circ {\text{C}} :
F = \dfrac{{9C}}{5} + 32 \\\ \Rightarrow F = \dfrac{{9 \times 70}}{5} + 32 \\\ \Rightarrow F = 126 + 32 \\\ \Rightarrow F = 158\,^\circ {\text{F}} \\\
So, the difference of temperature in the Fahrenheit scale:
ΔF=158F86F ΔF=72F\Delta F = 158\,^\circ {\text{F}} - 86\,^\circ {\text{F}} \\\ \therefore \Delta F = 72\,^\circ {\text{F}}

Hence, the temperature that has risen, equivalent to Fahrenheit is 72F72\,^\circ {\text{F}} .The correct option is D.

Note: While solving this problem, we should remember that the reading in the Fahrenheit scale is higher than the centigrade scale for the same temperature. We can also solve it by an alternative method with assuming any temperatures, by using the formula ΔC=59×ΔF\Delta C = \dfrac{5}{9} \times \Delta F . The formula features directly the difference in temperatures.