Question
Physics Question on thermal properties of matter
The temperature of a body is increased from −73∘C to 327∘C. Then the ratio of emissive power is
A
44570
B
44588
C
27-Jan
D
Jan-81
Answer
Jan-81
Explanation
Solution
Radiation from a body = R
R = e σT4 ? time ? area, where e = emissive power
? eT4 = constant or e =(T4constant)
or e2e1=(T1T2)4 or e2e1=(273−73273+327)4
=(200600)4=1(3)4=181
or e2e1=181