Solveeit Logo

Question

Question: The temperature of a \[3Kg\] block of aluminium raised by \(3\) degrees .How much heat would be need...

The temperature of a 3Kg3Kg block of aluminium raised by 33 degrees .How much heat would be needed to raise the temperature of a 9Kg9Kg block of aluminium by 33 degrees?
A. 9times9\,times As much heat as the 3Kg3Kg block
B. 3times3\,times As much heat as the 3Kg3Kg block
C. The same amount of heat as the 3Kg3Kg block
D. one-third as much heat as the 3Kg3Kg block
E. one-ninth as much heat as the 3Kg3Kg block

Explanation

Solution

In thermodynamics, specific heat of a substance is the minimum amount of heat required to raise the temperature of that substance by one degree Celsius and it’s denoted by SS . WE will use the general formula of relation between temperature raised and heat added to the system which is written as Q=mSΔTQ = mS\Delta T where mm is the mass of the substance which is raised by a temperature of ΔT\Delta T which has a specific heat value of SS.

Complete step by step answer:
Let us assume that specific heat of aluminium is denoted by SAl{S_{Al}} and let Qi{Q_i} be the heat given to the block of aluminium with mass of mi=3Kg{m_i} = 3Kg with the increases in temperature as given in question is ΔT=30C\Delta T = {3^0}C now, using the formula Q=mSΔTQ = mS\Delta T we have,
Qi=miSAlΔT{Q_i} = {m_i}{S_{Al}}\Delta T
On putting the values of given parameters we have,
Qi=9SAl(i){Q_i} = 9{S_{Al}} \to (i)
Now, let us assume that the heat required to raise the temperature of a mf=9Kg{m_f} = 9Kg block of aluminium by ΔT=30C\Delta T = {3^0}C is denoted by Qf{Q_f} again, by using the formula Q=mSΔTQ = mS\Delta T we have,
Qf=mfSAlΔT{Q_f} = {m_f}{S_{Al}}\Delta T
On putting the values of given parameters we have,
Qf=27SAl{Q_f} = 27{S_{Al}}
From equation Qi=9SAl(i){Q_i} = 9{S_{Al}} \to (i) put the value of SAl=Qi9{S_{Al}} = \dfrac{{{Q_i}}}{9} we get,
Qf=27×Qi9{Q_f} = 27 \times \dfrac{{{Q_i}}}{9}
Qf=3Qi\therefore {Q_f} = 3{Q_i}
So, we will need twice the amount of heat to raise the 9Kg9Kg block of aluminium by 33 degrees.

Hence, the correct option is B.

Note: It should be remembered that, the value of specific heat of any substance which is denoted by SS is a fixed constant value for that particular substance and units of heat is used as Joules whereas the SI units of specific heat of a substance is given by JKg1C1JK{g^{ - 1}}{C^{ - 1}} . And the value of specific heat is different for different materials.