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Question

Physics Question on thermal properties of matter

The temperature of 100 g of water is to be raised from 24?C to 90?C by adding steam to it. The mass of the steam required for this purpose is

A

10 g

B

12 g

C

14 g

D

16 g

Answer

12 g

Explanation

Solution

Let m be the mass of steam required.
By principle of calorimetry
100×1×(90−24)=m 540+m×1(100−90)100 \times 1 \times (90 - 24) = m \, 540 + m \times 1 (100 - 90)
i.e.,550m=100×66⇒ m=12gi.e., 550 m = 100 \times 66 \Rightarrow \, m = 12 g