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Question: The temperature gradient in a rod of 0.5 m long is \(80 ^ { \circ } \mathrm { C } / \mathrm { m }\)....

The temperature gradient in a rod of 0.5 m long is 80∘C/m80 ^ { \circ } \mathrm { C } / \mathrm { m }. If the temperature of hotter end of the rod is 30∘C30 ^ { \circ } \mathrm { C }, then the temperature of the cooler end is

A

40∘C40 ^ { \circ } \mathrm { C }

B

C

D

Answer

Explanation

Solution